## Given a tree, determine which edge to cut so that the resulting.

There is an undirected tree where each vertex is numbered from to, and each contains a data stumpmulching.club sum of a tree is the sum of all its nodes' data values. If an edge is cut, two smaller trees are formed. The difference between two trees is the absolute value of the difference in their sums.

### However, the only message I was getting about it was Runtime error, which is rather cryptic in this case.

Given a tree, determine which edge to cut so that the resulting trees have a minimal difference Estimated Reading Time: 2 mins. For those who are stuck, here are hints: 1. Dont think of it as a Tree problem. Approach it as a GRAPH. 2. Use first run of DFS to compute a value (not telling what it is:p) that you think will help you solve the problem.

3. The real breakthrough happens during the second run of stumpmulching.clubted Reading Time: 6 mins.

Cut Tree. Problem. Submissions. Leaderboard. Discussions. Editorial. Given a tree T with n nodes, how many subtrees (T') of T have at most K edges connected to (T - T')? Input Format. The first line contains two integers n and K followed by n-1 lines each containing two integers a & b denoting that there's an edge between a & stumpmulching.clubted Reading Time: 50 secs. This repository contains my solutions to easy and medium questions in Hackerrank.

Hope that helps.

- haotian-wu/Hackerrank_solutions. This problem is a simple application of Recursion and Depth First Traversal of a tree. You need to solve this problem using post order traversal technique, considering the tree as a rooted tree. Let's take the example given in the question. Cons.

### You have to look at your values from first run of DFS and identify what condition always holds true.

Given a tree T with n nodes, how many subtrees (T') of T have at most K edges connected to (T - T') We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.